Ana səhifə

Supplemental Table 1


Yüklə 84.5 Kb.
tarix27.06.2016
ölçüsü84.5 Kb.
Online Supplemental Materials

Supplemental Table 1. To determine whether the hormone solution affected fitness measures, we compared the progeny of cross-fertilizations from dioecious lineages in which the individuals to which the focal plants were outcrossed were either treated with hormone (males changed into females) or not treated with hormone (females left as females). A logit model was used to determine the effect of hormone treatment (a fixed effect) and lineage (a random effect) on whether a seed germinated and survived as a seedling (SAS Institute, 2004). We used mixed-model ANOVAs to test how the remaining fitness measures were affected by hormone treatment (a fixed effect) and lineage (a random effect). Proportion survival was analyzed on a per lineage basis, as it was for the analysis of cross type. For the ANOVA analyses, all fitness measures were log-transformed (Johnston and Schoen, 1994). Interaction terms with lineage were not included in these models, unlike in the models analyzing cross type, because only one hormone comparison was made per lineage.






















trait




hormone




lineage




error











































Proportion Germination & Early Survival

df = 1




df = 10












Χ2 = 0.12




Χ2 = 48.5












P = 0.73




P < 0.0001


























Proportion Late Survival

df = 1




df = 12




df = 21








MS = 0.02




MS = 0.11




MS = 0.02








F = 0.95




F = 0.56












P = 0.34




P = 0.85


























Plant Mass

df = 1




df = 12




df = 273








MS = 0.43




MS = 1.53




MS = 0.59








F = 0.73




F = 2.61












P = 0.39




P = 0.003


























Proportion Pollen Viability

df = 1




df = 11




df = 144








MS = 0.27




MS = 0.17




MS = 0.19








F = 1.44




F = 0.90












P = 0.23




P = 0.55


























Seed Mass

df = 1




df = 10




df = 69








MS = 0.07




MS = 2.56




MS = 1.23








F = 0.06




F = 2.10












P = 0.81




P = 0.036






 

 























Verilənlər bazası müəlliflik hüququ ilə müdafiə olunur ©atelim.com 2016
rəhbərliyinə müraciət