光學作業 0932348 李正偉
11-25
We have shown that the secondary maxima in a single-slit diffraction pattern do not fall exactly halfway between minima, but are quite close. Assuming they are halfway:
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Show that the irradiance of the mth secondary peak is given approximately by
II
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Calculate the percent error involved in this apprpximation for the first three secondary maxima.
Ans.
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I= I()
已知maxima 約在 zeros 中間
又 zeros : =m m=, ,…
maxima: =(m+)
II= I
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估計值: I= I=0.0450
理論值: I= I=0.0472
誤差4.6%
估計值:I= I=0.0162
理論值: I= I=0.0165
誤差1.7%
估計值:I= I=8.27m
理論值: I= I=8.34m
誤差0.84% |