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Show that the irradiance of the mth secondary peak is given approximately by


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光學作業 0932348 李正偉

11-25


We have shown that the secondary maxima in a single-slit diffraction pattern do not fall exactly halfway between minima, but are quite close. Assuming they are halfway:


  1. Show that the irradiance of the mth secondary peak is given approximately by

II

  1. Calculate the percent error involved in this apprpximation for the first three secondary maxima.

Ans.



  1. I= I()

已知maxima 約在 zeros 中間

又 zeros : =m m=, ,…



maxima: =(m+)

II= I




  1. 估計值: I= I=0.0450

理論值: I= I=0.0472
誤差4.6%
估計值:I= I=0.0162

理論值: I= I=0.0165

誤差1.7%
估計值:I= I=8.27m

理論值: I= I=8.34m



誤差0.84%


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